⁦Derivatives of sine, exponentials, logs and inverses⁩

⁦Test the derivative of sin x near zero, draw the tangent to ex, use ln x as the mirror image of ex to find its derivative, and carry the inverse-function rule over to arctan⁩.

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الدليل

⁦(sin x)′ = cos x and (cos x)′ = −sin x⁩. ⁦Near 0 the curve sin x hugs the line y = x, so its gradient there is 1, which is cos 0⁩.

(ex)′ = ex: ⁦at every point the gradient of the curve equals its height⁩. ⁦ln x is the inverse of ex, and (ln x)′ = ١x⁩.

⁦If f(a) = b, the inverse function has derivative (f−١)′(b) = ١f′(a) at b⁩. ⁦The inverse curve is the mirror image of f in y = x, so the gradients are flipped⁩.