⁦Area of the orthogonal projection of a polygon⁩

⁦Use the theorem on the area of a projection, S′ = S · cos α, to find the area of a projection or of the polygon itself⁩.

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الدليل

⁦From the Ukrainian Grade 10 textbook (algebra and calculus with geometry)⁩, §5 '⁦Perpendicularity in space⁩', ⁦item 37⁩ '⁦Dihedral angle⁩. ⁦The angle between planes⁩'. ⁦The orthogonal projection of a polygon onto a plane is the polygon formed by the projections of all its points onto that plane⁩.

⁦Theorem 37.1 (area of the orthogonal projection of a polygon)⁩. ⁦The area of the projection of a convex polygon equals the product of its area and the cosine of the angle α between the polygon and its projection, where 0° ≤ α < 90°⁩: S′ = S·cosα.

⁦So the projection is never larger than the polygon itself⁩. ⁦To find the polygon⁩'⁦s area from the area of its projection, divide by the cosine⁩: S = S′ : cosα.

⁦Set the solution out as the textbook does⁩: ⁦the area of the polygon, then the angle, then the formula, and finally the answer⁩.